(x+y)(x^2+3xy+y^2)=0

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Solution for (x+y)(x^2+3xy+y^2)=0 equation:


Simplifying
(x + y)(x2 + 3xy + y2) = 0

Reorder the terms:
(x + y)(3xy + x2 + y2) = 0

Multiply (x + y) * (3xy + x2 + y2)
(x(3xy + x2 + y2) + y(3xy + x2 + y2)) = 0
((3xy * x + x2 * x + y2 * x) + y(3xy + x2 + y2)) = 0

Reorder the terms:
((xy2 + 3x2y + x3) + y(3xy + x2 + y2)) = 0
((xy2 + 3x2y + x3) + y(3xy + x2 + y2)) = 0
(xy2 + 3x2y + x3 + (3xy * y + x2 * y + y2 * y)) = 0
(xy2 + 3x2y + x3 + (3xy2 + x2y + y3)) = 0

Reorder the terms:
(xy2 + 3xy2 + 3x2y + x2y + x3 + y3) = 0

Combine like terms: xy2 + 3xy2 = 4xy2
(4xy2 + 3x2y + x2y + x3 + y3) = 0

Combine like terms: 3x2y + x2y = 4x2y
(4xy2 + 4x2y + x3 + y3) = 0

Solving
4xy2 + 4x2y + x3 + y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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